The red LED's given voltage and current ratings were 5V and 22.75mA respectively, yellow's were 2V and 20mA.
The LEDs were placed in a circuit in parallel with a resistor (R1 and R2) in series on each. A 9V supply was given by a power supply.
Ohm's Law was used to calculate the equivalent resistances of the LEDs.
RLED1 = 219.8Ω, RLED2 = 100Ω
Using the current and voltage ratings, theoretical voltages and resistances values were found for R1 and R2.
V1 = 4V, V2 = 7V
R1 = 176Ω, R2 = 350Ω
We only had access to 100, 150, 220, 360, and 470-Ohm resistors, so we approximated R1 with a 150Ω and R2 with a 360Ω. Their measured values were 148.2Ω and 360Ω respectively. Both were quarter-watt resistors.
Three configurations were used:
- Both LEDs in the circuit
- Without LED2
- Without LED1
These are the results:
Using this data, I calculated a few things.
a) If the supply was just a 9V battery with a 0.2 A-hr capacity of useful voltage, the circuit in config1 would last 4.68 hours.
b) The % error between experimental and desired values of LED current were 36.3% for LED1 and 1.45% for LED2. This was caused by resistor restrictions.
c) The efficiency of the circuit in configuration 1 was found to be 40.8%, which is pretty poor.
d) Assuming current is the same, if a 6V battery was used instead of a 9V battery, ... I really don't understand this problem.
Oh, yeah, and we blew up a red LED by overloading it with voltage.
Configuration | I of LED1 (mA) | V of LED1 (V) | I of LED2 (mA) | V of LED2 (V) | I of supply (mA) |
1 | 14.5 | 6.68 | 19.71 | 19.71 | 35.1 |
2 | 14.8 | 6.74 | NA | NA | 15.1 |
3 | NA | NA | 20.2 | 1.65 | 20.3 |
Using this data, I calculated a few things.
a) If the supply was just a 9V battery with a 0.2 A-hr capacity of useful voltage, the circuit in config1 would last 4.68 hours.
b) The % error between experimental and desired values of LED current were 36.3% for LED1 and 1.45% for LED2. This was caused by resistor restrictions.
c) The efficiency of the circuit in configuration 1 was found to be 40.8%, which is pretty poor.
d) Assuming current is the same, if a 6V battery was used instead of a 9V battery, ... I really don't understand this problem.
Oh, yeah, and we blew up a red LED by overloading it with voltage.
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