In this lab, a 741 op-amp was used to create inverting amplifier circuit under the pretense of creating a signal conditioning circuit for a sensor.
A voltage divider was devised to get a voltage of one volt for the VIN and mimic a sensor's output.
The following data was collected on the components we used.
Above is the layout of our circuits.
IV1 = 8.95 mA
IV2 = 0.95 mA
Because these aren't equal to each other, we couldn't go on to the last page of the lab because he lab was written in anticipation of each group getting a 3rd voltage source, but only 2 were available for each.
Saturday, April 30, 2011
Monday, April 4, 2011
Equivalents HW using PSpice
Thevenin and Norton Equivalents in PSpice
We modeled circuits in PSpice and used DC sweeps to o determine their Thevenin and Norton equivalents.
In order to do this in the first circuit, we placed a current source I2 across the terminals that we were interested in and then used a DC Sweep to change it's value from 0A to 1.0A. After running the simulation, a trace of "V(I2:-)" was added to plot the voltage across the current source I2.
The y-intercept gave the Vth and the slope of the line gave the Rth because V=I*Rth.
Thus, the Vth = 20V and Rth = 6 Ohms.
Then we worked out the Norton equivalent. We did this by replacing the current source I2 with a Voltage source that was varied from 0 volts to 1.0V by increments of 0.1V.
Here the y-intercept gave us the IN = 3.335 A and the slope gave GN = 0.17 S.
In the last problem, I found the load that maximizes the power dissipation.
I put a resistor across the terminals that had values of { RL } and I set RL's value with a Global Parameter. This global parameter was swept from 100Ohms to 5kOhms with 100Ohm increments. I ran the simulation and got the following graphs. The top one was arrived at through a linear sweep, and the bottom through a octave sweep. The peaks show at 250microW with RL = 1kOhm, as expected.
Friday, April 1, 2011
Thevenin Equivalents' Equity
The purpose of this lab was to find a Thevenin equivalent of a circuit and model it to see how accurate it was.
The VTh = 8.65V,
the RTh = 66.0Ω,
and the ITh = 131mA.
Here's a picture of our circuit.
Here's a the table of the components we used.
Here's a table of the results we got from those components followed by another table of components we used.
However, the components in the seoncd table didn't really get the time needed to be used. We had started the lab too late and had to leave. Instead of making the whole class come back on Friday to finish the last page of the lab, Professor Mason allowed us to call it quits.
The VTh = 8.65V,
the RTh = 66.0Ω,
and the ITh = 131mA.
Here's a picture of our circuit.
Here's a the table of the components we used.
Here's a table of the results we got from those components followed by another table of components we used.
However, the components in the seoncd table didn't really get the time needed to be used. We had started the lab too late and had to leave. Instead of making the whole class come back on Friday to finish the last page of the lab, Professor Mason allowed us to call it quits.
Wednesday, March 23, 2011
PSpice Fun
After installing PSpice, I had to run Capture Student as administrator to get the PSpice menu to show up in it.
I had to import some libraries to get the parts I need to use, and then it was simply place parts in a sensible pattern and connecting them with wire.
Below is my PSpice for working out the last problem of the 8th WebAssign assignment.
I had to import some libraries to get the parts I need to use, and then it was simply place parts in a sensible pattern and connecting them with wire.
Below is my PSpice for working out the last problem of the 8th WebAssign assignment.
Tuesday, March 22, 2011
More pictures from Node Analysis
Friday, March 18, 2011
Nodal Analysis is for Knowing Nerd Noggins
We (James Dunn and I) used nodal analysis to determine the theoretical voltage between two points and a reference node AKA "ground" and the currents coming from two voltage sources.
Our theorectical values for V2 and V3 were 10.26V and 8.67V respectively.
We determined that IBat 1 and IBat 2 were 17.4mA and 1.48mA, which would give power supplies of 208.8mW and 13.35mW respectively.
In the last part, for extra fun, we figured out what voltages we would need to load across the circuit to make both V2 and V3 equal 9V. We worked out that VL1 would be 9.9V and VL2 would be 10.98V. To get these particular load voltages, we would need to use a voltage divider to bring 12V down to these voltages.
We did this with a resistor box of 213Ω in series with Vbat1 and 103Ω in series with Vbat2. We got as close as 9.09V for V2 and 8.99V for V3, after fiddling with the resistances a bit. :) Our currents became 9.90mA and 8.61mA for Ibat1 and Ibat2 respectively.
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| Circuit Diagram |
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| I'll get a better picture from James soon. |
Our theorectical values for V2 and V3 were 10.26V and 8.67V respectively.
We determined that IBat 1 and IBat 2 were 17.4mA and 1.48mA, which would give power supplies of 208.8mW and 13.35mW respectively.
In the last part, for extra fun, we figured out what voltages we would need to load across the circuit to make both V2 and V3 equal 9V. We worked out that VL1 would be 9.9V and VL2 would be 10.98V. To get these particular load voltages, we would need to use a voltage divider to bring 12V down to these voltages.
We did this with a resistor box of 213Ω in series with Vbat1 and 103Ω in series with Vbat2. We got as close as 9.09V for V2 and 8.99V for V3, after fiddling with the resistances a bit. :) Our currents became 9.90mA and 8.61mA for Ibat1 and Ibat2 respectively.
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